2x^2=1058

Solution for 2x^2=1058 equation:

2x^2=1058

We move all terms to the left:

2x^2-(1058)=0

a = 2; b = 0; c = -1058;
Δ = b2-4ac
Δ = 02-4·2·(-1058)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-92}{2*2}=\frac{-92}{4}
=-23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+92}{2*2}=\frac{92}{4}
=23
$